Base | Representation |
---|---|
bin | 10111101011110100011001… |
… | …00100001100001001010001 |
3 | 20211102002200000000110221001 |
4 | 23311322030210030021101 |
5 | 23311312223210302330 |
6 | 302434354351502001 |
7 | 13653611362103365 |
oct | 1365721444141121 |
9 | 224362600013831 |
10 | 52083131728465 |
11 | 156603720689a2 |
12 | 5a12087527901 |
13 | 230a558b75b06 |
14 | cc0ba0b292a5 |
15 | 604c060209ca |
hex | 2f5e8c90c251 |
52083131728465 has 16 divisors (see below), whose sum is σ = 62569851438528. Its totient is φ = 41619778220736.
The previous prime is 52083131728387. The next prime is 52083131728483. The reversal of 52083131728465 is 56482713138025.
It is a cyclic number.
It is not a de Polignac number, because 52083131728465 - 29 = 52083131727953 is a prime.
It is a super-2 number, since 2×520831317284652 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 408870874 + ... + 408998236.
It is an arithmetic number, because the mean of its divisors is an integer number (3910615714908).
Almost surely, 252083131728465 is an apocalyptic number.
It is an amenable number.
52083131728465 is a deficient number, since it is larger than the sum of its proper divisors (10486719710063).
52083131728465 is a wasteful number, since it uses less digits than its factorization.
52083131728465 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 218448.
The product of its (nonzero) digits is 9676800, while the sum is 55.
The spelling of 52083131728465 in words is "fifty-two trillion, eighty-three billion, one hundred thirty-one million, seven hundred twenty-eight thousand, four hundred sixty-five".
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