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52105130244332 = 22111184207505553
BaseRepresentation
bin10111101100011101010111…
…10001110111100011101100
320211111012110010002212112222
423312032223301313203230
523312142301320304312
6302452433312214512
713655320462311224
oct1366165361674354
9224435403085488
1052105130244332
1115669730710520
125a163a683a438
13230c6535c83c9
14cc1c8a601084
15605592459672
hex2f63abc778ec

52105130244332 has 12 divisors (see below), whose sum is σ = 99473430466536. Its totient is φ = 23684150111040.

The previous prime is 52105130244331. The next prime is 52105130244341. The reversal of 52105130244332 is 23344203150125.

It is a junction number, because it is equal to n+sod(n) for n = 52105130244292 and 52105130244301.

It is not an unprimeable number, because it can be changed into a prime (52105130244331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 592103752733 + ... + 592103752820.

It is an arithmetic number, because the mean of its divisors is an integer number (8289452538878).

Almost surely, 252105130244332 is an apocalyptic number.

It is an amenable number.

52105130244332 is a deficient number, since it is larger than the sum of its proper divisors (47368300222204).

52105130244332 is a wasteful number, since it uses less digits than its factorization.

52105130244332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1184207505568 (or 1184207505566 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 52105130244332 its reverse (23344203150125), we get a palindrome (75449333394457).

The spelling of 52105130244332 in words is "fifty-two trillion, one hundred five billion, one hundred thirty million, two hundred forty-four thousand, three hundred thirty-two".

Divisors: 1 2 4 11 22 44 1184207505553 2368415011106 4736830022212 13026282561083 26052565122166 52105130244332