Base | Representation |
---|---|
bin | 100101111010011011010… |
… | …1010111000110011000011 |
3 | 200110010202111221100110100 |
4 | 1023310312222320303003 |
5 | 1140333014402324103 |
6 | 15025433541333443 |
7 | 1045314212551164 |
oct | 113646652706303 |
9 | 20403674840410 |
10 | 5210712542403 |
11 | 172993a429395 |
12 | 701a55107283 |
13 | 2ba4a28b1b14 |
14 | 1402b24ab76b |
15 | 908213a25a3 |
hex | 4bd36ab8cc3 |
5210712542403 has 12 divisors (see below), whose sum is σ = 7529383845880. Its totient is φ = 3472516486656.
The previous prime is 5210712542341. The next prime is 5210712542423. The reversal of 5210712542403 is 3042452170125.
5210712542403 is a `hidden beast` number, since 5 + 2 + 1 + 0 + 71 + 2 + 542 + 40 + 3 = 666.
It is not a de Polignac number, because 5210712542403 - 210 = 5210712541379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5210712542423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 107630701 + ... + 107679102.
Almost surely, 25210712542403 is an apocalyptic number.
5210712542403 is a deficient number, since it is larger than the sum of its proper divisors (2318671303477).
5210712542403 is a wasteful number, since it uses less digits than its factorization.
5210712542403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 215312498 (or 215312495 counting only the distinct ones).
The product of its (nonzero) digits is 67200, while the sum is 36.
The spelling of 5210712542403 in words is "five trillion, two hundred ten billion, seven hundred twelve million, five hundred forty-two thousand, four hundred three".
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