Base | Representation |
---|---|
bin | 100101111010101101110… |
… | …0100001111000010111101 |
3 | 200110012100122201110210222 |
4 | 1023311123210033002331 |
5 | 1140340301334234032 |
6 | 15030015213111125 |
7 | 1045335440226143 |
oct | 113653344170275 |
9 | 20405318643728 |
10 | 5211331555517 |
11 | 172a12789307a |
12 | 701ba84884a5 |
13 | 2ba570c06879 |
14 | 1403307a3593 |
15 | 9085a8c8a12 |
hex | 4bd5b90f0bd |
5211331555517 has 2 divisors, whose sum is σ = 5211331555518. Its totient is φ = 5211331555516.
The previous prime is 5211331555513. The next prime is 5211331555543. The reversal of 5211331555517 is 7155551331125.
5211331555517 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4118196483556 + 1093135071961 = 2029334^2 + 1045531^2 .
It is a cyclic number.
It is not a de Polignac number, because 5211331555517 - 22 = 5211331555513 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5211331555513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2605665777758 + 2605665777759.
It is an arithmetic number, because the mean of its divisors is an integer number (2605665777759).
Almost surely, 25211331555517 is an apocalyptic number.
It is an amenable number.
5211331555517 is a deficient number, since it is larger than the sum of its proper divisors (1).
5211331555517 is an equidigital number, since it uses as much as digits as its factorization.
5211331555517 is an evil number, because the sum of its binary digits is even.
The product of its digits is 393750, while the sum is 44.
The spelling of 5211331555517 in words is "five trillion, two hundred eleven billion, three hundred thirty-one million, five hundred fifty-five thousand, five hundred seventeen".
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