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521140016113 is a prime number
BaseRepresentation
bin1111001010101100101…
…11011001001111110001
31211211011010212210121021
413211112113121033301
532014243321003423
61035224115055441
752436223022363
oct7452627311761
91754133783537
10521140016113
11191017a534a2
12850008a1581
133a1b2a77352
141b31aaa2d33
15d8519db95d
hex79565d93f1

521140016113 has 2 divisors, whose sum is σ = 521140016114. Its totient is φ = 521140016112.

The previous prime is 521140016093. The next prime is 521140016143. The reversal of 521140016113 is 311610041125.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 520038572769 + 1101443344 = 721137^2 + 33188^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-521140016113 is a prime.

It is not a weakly prime, because it can be changed into another prime (521140016143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 260570008056 + 260570008057.

It is an arithmetic number, because the mean of its divisors is an integer number (260570008057).

Almost surely, 2521140016113 is an apocalyptic number.

It is an amenable number.

521140016113 is a deficient number, since it is larger than the sum of its proper divisors (1).

521140016113 is an equidigital number, since it uses as much as digits as its factorization.

521140016113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 521140016113 its reverse (311610041125), we get a palindrome (832750057238).

The spelling of 521140016113 in words is "five hundred twenty-one billion, one hundred forty million, sixteen thousand, one hundred thirteen".