Base | Representation |
---|---|
bin | 10111101100101101111111… |
… | …00000101000100100111001 |
3 | 20211112001110211110122120200 |
4 | 23312112333200220210321 |
5 | 23312314034102033213 |
6 | 302500510431312413 |
7 | 13656054525241200 |
oct | 1366267740504471 |
9 | 224461424418520 |
10 | 52114051205433 |
11 | 15672499327648 |
12 | 5a1807637b709 |
13 | 2310445893909 |
14 | cc2495320237 |
15 | 605915722273 |
hex | 2f65bf828939 |
52114051205433 has 54 divisors (see below), whose sum is σ = 93019711379166. Its totient is φ = 28027724949504.
The previous prime is 52114051205431. The next prime is 52114051205441. The reversal of 52114051205433 is 33450215041125.
52114051205433 is a `hidden beast` number, since 5 + 2 + 1 + 1 + 40 + 51 + 20 + 543 + 3 = 666.
It can be written as a sum of positive squares in 3 ways, for example, as 31762376899344 + 20351674306089 = 5635812^2 + 4511283^2 .
It is not a de Polignac number, because 52114051205433 - 21 = 52114051205431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (52114051205431) by changing a digit.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 204323160 + ... + 204578057.
Almost surely, 252114051205433 is an apocalyptic number.
It is an amenable number.
52114051205433 is a deficient number, since it is larger than the sum of its proper divisors (40905660173733).
52114051205433 is a wasteful number, since it uses less digits than its factorization.
52114051205433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 408901271 (or 408901244 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 52114051205433 its reverse (33450215041125), we get a palindrome (85564266246558).
The spelling of 52114051205433 in words is "fifty-two trillion, one hundred fourteen billion, fifty-one million, two hundred five thousand, four hundred thirty-three".
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