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521314212113 = 1730665541889
BaseRepresentation
bin1111001011000001011…
…11111001100100010001
31211211121021122212120222
413211200233321210101
532020122414241423
61035253300442425
752443436455422
oct7454057714421
91754537585528
10521314212113
111910a7311532
128504b0a9415
133a20cb984c6
141b335c89649
15d861e4a3c8
hex7960bf9911

521314212113 has 4 divisors (see below), whose sum is σ = 551979754020. Its totient is φ = 490648670208.

The previous prime is 521314212053. The next prime is 521314212119. The reversal of 521314212113 is 311212413125.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 467373220609 + 53940991504 = 683647^2 + 232252^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-521314212113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (521314212119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15332770928 + ... + 15332770961.

It is an arithmetic number, because the mean of its divisors is an integer number (137994938505).

Almost surely, 2521314212113 is an apocalyptic number.

It is an amenable number.

521314212113 is a deficient number, since it is larger than the sum of its proper divisors (30665541907).

521314212113 is a wasteful number, since it uses less digits than its factorization.

521314212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30665541906.

The product of its digits is 1440, while the sum is 26.

Adding to 521314212113 its reverse (311212413125), we get a palindrome (832526625238).

The spelling of 521314212113 in words is "five hundred twenty-one billion, three hundred fourteen million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 17 30665541889 521314212113