Base | Representation |
---|---|
bin | 1111001011000001011… |
… | …11111001100100010001 |
3 | 1211211121021122212120222 |
4 | 13211200233321210101 |
5 | 32020122414241423 |
6 | 1035253300442425 |
7 | 52443436455422 |
oct | 7454057714421 |
9 | 1754537585528 |
10 | 521314212113 |
11 | 1910a7311532 |
12 | 8504b0a9415 |
13 | 3a20cb984c6 |
14 | 1b335c89649 |
15 | d861e4a3c8 |
hex | 7960bf9911 |
521314212113 has 4 divisors (see below), whose sum is σ = 551979754020. Its totient is φ = 490648670208.
The previous prime is 521314212053. The next prime is 521314212119. The reversal of 521314212113 is 311212413125.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 467373220609 + 53940991504 = 683647^2 + 232252^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-521314212113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (521314212119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15332770928 + ... + 15332770961.
It is an arithmetic number, because the mean of its divisors is an integer number (137994938505).
Almost surely, 2521314212113 is an apocalyptic number.
It is an amenable number.
521314212113 is a deficient number, since it is larger than the sum of its proper divisors (30665541907).
521314212113 is a wasteful number, since it uses less digits than its factorization.
521314212113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30665541906.
The product of its digits is 1440, while the sum is 26.
Adding to 521314212113 its reverse (311212413125), we get a palindrome (832526625238).
The spelling of 521314212113 in words is "five hundred twenty-one billion, three hundred fourteen million, two hundred twelve thousand, one hundred thirteen".
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