Base | Representation |
---|---|
bin | 110000100011101011… |
… | …000110110111000011 |
3 | 11222120121001102201001 |
4 | 300203223012313003 |
5 | 1323234324013103 |
6 | 35541340352431 |
7 | 3524013424531 |
oct | 604353066703 |
9 | 158517042631 |
10 | 52138110403 |
11 | 20125671045 |
12 | a130b45717 |
13 | 4bbba12302 |
14 | 274869b151 |
15 | 155243901d |
hex | c23ac6dc3 |
52138110403 has 8 divisors (see below), whose sum is σ = 53588774960. Its totient is φ = 50689631520.
The previous prime is 52138110383. The next prime is 52138110457. The reversal of 52138110403 is 30401183125.
It is a happy number.
52138110403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52138110403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52138110473) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 497988 + ... + 593521.
It is an arithmetic number, because the mean of its divisors is an integer number (6698596870).
Almost surely, 252138110403 is an apocalyptic number.
52138110403 is a deficient number, since it is larger than the sum of its proper divisors (1450664557).
52138110403 is a wasteful number, since it uses less digits than its factorization.
52138110403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1092837.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 52138110403 its reverse (30401183125), we get a palindrome (82539293528).
The spelling of 52138110403 in words is "fifty-two billion, one hundred thirty-eight million, one hundred ten thousand, four hundred three".
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