Base | Representation |
---|---|
bin | 110000100011110100… |
… | …101110110101111111 |
3 | 11222120202210121201000 |
4 | 300203310232311333 |
5 | 1323241000232341 |
6 | 35541510421343 |
7 | 3524044033443 |
oct | 604364566577 |
9 | 158522717630 |
10 | 52140633471 |
11 | 20127034723 |
12 | a131961853 |
13 | 4bbc3b6854 |
14 | 2748b56823 |
15 | 15527868b6 |
hex | c23d2ed7f |
52140633471 has 8 divisors (see below), whose sum is σ = 77245382960. Its totient is φ = 34760422296.
The previous prime is 52140633439. The next prime is 52140633487. The reversal of 52140633471 is 17433604125.
52140633471 is a `hidden beast` number, since 5 + 2 + 14 + 0 + 633 + 4 + 7 + 1 = 666.
It is not a de Polignac number, because 52140633471 - 25 = 52140633439 is a prime.
It is a super-3 number, since 3×521406334713 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52140633421) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 965567260 + ... + 965567313.
It is an arithmetic number, because the mean of its divisors is an integer number (9655672870).
Almost surely, 252140633471 is an apocalyptic number.
52140633471 is a deficient number, since it is larger than the sum of its proper divisors (25104749489).
52140633471 is a wasteful number, since it uses less digits than its factorization.
52140633471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1931134582 (or 1931134576 counting only the distinct ones).
The product of its (nonzero) digits is 60480, while the sum is 36.
The spelling of 52140633471 in words is "fifty-two billion, one hundred forty million, six hundred thirty-three thousand, four hundred seventy-one".
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