Base | Representation |
---|---|
bin | 10111101111011010111010… |
… | …01111110100100011101111 |
3 | 20211211221010001122011201101 |
4 | 23313231131033310203233 |
5 | 23320324203312131112 |
6 | 303011303130023531 |
7 | 13665552310231312 |
oct | 1367553517644357 |
9 | 224757101564641 |
10 | 52206891911407 |
11 | 156a89004a9122 |
12 | 5a32066577ba7 |
13 | 23191200960ac |
14 | cc6b815da979 |
15 | 60804b179757 |
hex | 2f7b5d3f48ef |
52206891911407 has 2 divisors, whose sum is σ = 52206891911408. Its totient is φ = 52206891911406.
The previous prime is 52206891911381. The next prime is 52206891911429. The reversal of 52206891911407 is 70411919860225.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52206891911407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52206891911437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26103445955703 + 26103445955704.
It is an arithmetic number, because the mean of its divisors is an integer number (26103445955704).
Almost surely, 252206891911407 is an apocalyptic number.
52206891911407 is a deficient number, since it is larger than the sum of its proper divisors (1).
52206891911407 is an equidigital number, since it uses as much as digits as its factorization.
52206891911407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2177280, while the sum is 55.
The spelling of 52206891911407 in words is "fifty-two trillion, two hundred six billion, eight hundred ninety-one million, nine hundred eleven thousand, four hundred seven".
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