Base | Representation |
---|---|
bin | 110000101001001101… |
… | …111011000001101011 |
3 | 11222211002001222001221 |
4 | 300221031323001223 |
5 | 1323432131414201 |
6 | 35554502122511 |
7 | 3526223135452 |
oct | 605115730153 |
9 | 158732058057 |
10 | 52231123051 |
11 | 2017311a8a8 |
12 | a158120437 |
13 | 4c0507a593 |
14 | 2756b8db99 |
15 | 155a6ad4a1 |
hex | c2937b06b |
52231123051 has 4 divisors (see below), whose sum is σ = 55303542072. Its totient is φ = 49158704032.
The previous prime is 52231123033. The next prime is 52231123079. The reversal of 52231123051 is 15032113225.
52231123051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52231123051 - 215 = 52231090283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (52231123951) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1536209485 + ... + 1536209518.
It is an arithmetic number, because the mean of its divisors is an integer number (13825885518).
Almost surely, 252231123051 is an apocalyptic number.
52231123051 is a deficient number, since it is larger than the sum of its proper divisors (3072419021).
52231123051 is a wasteful number, since it uses less digits than its factorization.
52231123051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3072419020.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 52231123051 its reverse (15032113225), we get a palindrome (67263236276).
The spelling of 52231123051 in words is "fifty-two billion, two hundred thirty-one million, one hundred twenty-three thousand, fifty-one".
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