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52253311331129 is a prime number
BaseRepresentation
bin10111110000110001011000…
…00011110110101100111001
320212000100221002222000120212
423320120230003312230321
523322104240200044004
6303044501223200505
714002114523623436
oct1370305403665471
9225010832860525
1052253311331129
1115716561007217
125a3b0602a6135
13232060a094c5c
14cc9106594b8d
156093664e696e
hex2f862c0f6b39

52253311331129 has 2 divisors, whose sum is σ = 52253311331130. Its totient is φ = 52253311331128.

The previous prime is 52253311331087. The next prime is 52253311331171. The reversal of 52253311331129 is 92113311335225.

It is a balanced prime because it is at equal distance from previous prime (52253311331087) and next prime (52253311331171).

It can be written as a sum of positive squares in only one way, i.e., 50157939279529 + 2095372051600 = 7082227^2 + 1447540^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-52253311331129 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (52253311331189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26126655665564 + 26126655665565.

It is an arithmetic number, because the mean of its divisors is an integer number (26126655665565).

Almost surely, 252253311331129 is an apocalyptic number.

It is an amenable number.

52253311331129 is a deficient number, since it is larger than the sum of its proper divisors (1).

52253311331129 is an equidigital number, since it uses as much as digits as its factorization.

52253311331129 is an evil number, because the sum of its binary digits is even.

The product of its digits is 145800, while the sum is 41.

The spelling of 52253311331129 in words is "fifty-two trillion, two hundred fifty-three billion, three hundred eleven million, three hundred thirty-one thousand, one hundred twenty-nine".