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52300613533 = 77471516219
BaseRepresentation
bin110000101101010111…
…000000011110011101
311222222220211110002111
4300231113000132131
51324102424113113
640005423354021
73531025610560
oct605527003635
9158886743074
1052300613533
11201a9373053
12a177452911
134c1659b1cc
1427620bc4d7
15156183813d
hexc2d5c079d

52300613533 has 4 divisors (see below), whose sum is σ = 59772129760. Its totient is φ = 44829097308.

The previous prime is 52300613531. The next prime is 52300613647. The reversal of 52300613533 is 33531600325.

52300613533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 52300613533 - 21 = 52300613531 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52300613495 and 52300613504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52300613531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3735758103 + ... + 3735758116.

It is an arithmetic number, because the mean of its divisors is an integer number (14943032440).

Almost surely, 252300613533 is an apocalyptic number.

It is an amenable number.

52300613533 is a deficient number, since it is larger than the sum of its proper divisors (7471516227).

52300613533 is an equidigital number, since it uses as much as digits as its factorization.

52300613533 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7471516226.

The product of its (nonzero) digits is 24300, while the sum is 31.

The spelling of 52300613533 in words is "fifty-two billion, three hundred million, six hundred thirteen thousand, five hundred thirty-three".

Divisors: 1 7 7471516219 52300613533