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52304042415133 is a prime number
BaseRepresentation
bin10111110010001111110111…
…10111100101010000011101
320212012012212122110002221001
423321013323313211100131
523323422134324241013
6303124051222310301
714005561634002435
oct1371077367452035
9225165778402831
1052304042415133
111573602441a523
125a48a59b88391
132325333438562
14ccb75a0312c5
1560a83514dddd
hex2f91fbde541d

52304042415133 has 2 divisors, whose sum is σ = 52304042415134. Its totient is φ = 52304042415132.

The previous prime is 52304042415061. The next prime is 52304042415161. The reversal of 52304042415133 is 33151424040325.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32690641010329 + 19613401404804 = 5717573^2 + 4428702^2 .

It is a cyclic number.

It is not a de Polignac number, because 52304042415133 - 217 = 52304042284061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 52304042415092 and 52304042415101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52304042419133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26152021207566 + 26152021207567.

It is an arithmetic number, because the mean of its divisors is an integer number (26152021207567).

Almost surely, 252304042415133 is an apocalyptic number.

It is an amenable number.

52304042415133 is a deficient number, since it is larger than the sum of its proper divisors (1).

52304042415133 is an equidigital number, since it uses as much as digits as its factorization.

52304042415133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 52304042415133 its reverse (33151424040325), we get a palindrome (85455466455458).

The spelling of 52304042415133 in words is "fifty-two trillion, three hundred four billion, forty-two million, four hundred fifteen thousand, one hundred thirty-three".