Base | Representation |
---|---|
bin | 110000101110001011… |
… | …101001100110011111 |
3 | 12000000212210120001022 |
4 | 300232023221212133 |
5 | 1324114442212341 |
6 | 40011035234355 |
7 | 3531254114615 |
oct | 605613514637 |
9 | 160025716038 |
10 | 52314413471 |
11 | 20206139161 |
12 | a17bba89bb |
13 | 4c193c0558 |
14 | 2763c716b5 |
15 | 1562b61e4b |
hex | c2e2e999f |
52314413471 has 2 divisors, whose sum is σ = 52314413472. Its totient is φ = 52314413470.
The previous prime is 52314413449. The next prime is 52314413539. The reversal of 52314413471 is 17431441325.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52314413471 - 226 = 52247304607 is a prime.
It is a super-3 number, since 3×523144134713 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52314416471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26157206735 + 26157206736.
It is an arithmetic number, because the mean of its divisors is an integer number (26157206736).
Almost surely, 252314413471 is an apocalyptic number.
52314413471 is a deficient number, since it is larger than the sum of its proper divisors (1).
52314413471 is an equidigital number, since it uses as much as digits as its factorization.
52314413471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 40320, while the sum is 35.
Adding to 52314413471 its reverse (17431441325), we get a palindrome (69745854796).
The spelling of 52314413471 in words is "fifty-two billion, three hundred fourteen million, four hundred thirteen thousand, four hundred seventy-one".
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