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5233132151249 is a prime number
BaseRepresentation
bin100110000100110111011…
…1110111010000111010001
3200112021121222101111001112
41030021232332322013101
51141214423312314444
615044022343343105
71050036615231242
oct114115676720721
920467558344045
105233132151249
1117383a4743342
12706271451a95
132bc63664c762
141413dbc78cc9
15911d476969e
hex4c26efba1d1

5233132151249 has 2 divisors, whose sum is σ = 5233132151250. Its totient is φ = 5233132151248.

The previous prime is 5233132151197. The next prime is 5233132151333. The reversal of 5233132151249 is 9421512313325.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4880533711249 + 352598440000 = 2209193^2 + 593800^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5233132151249 is a prime.

It is a super-2 number, since 2×52331321512492 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5233932151249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2616566075624 + 2616566075625.

It is an arithmetic number, because the mean of its divisors is an integer number (2616566075625).

Almost surely, 25233132151249 is an apocalyptic number.

It is an amenable number.

5233132151249 is a deficient number, since it is larger than the sum of its proper divisors (1).

5233132151249 is an equidigital number, since it uses as much as digits as its factorization.

5233132151249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 194400, while the sum is 41.

The spelling of 5233132151249 in words is "five trillion, two hundred thirty-three billion, one hundred thirty-two million, one hundred fifty-one thousand, two hundred forty-nine".