Base | Representation |
---|---|
bin | 100110000100111010011… |
… | …0101011001110111111101 |
3 | 200112021212211010010122121 |
4 | 1030021310311121313331 |
5 | 1141220123430320242 |
6 | 15044040211442541 |
7 | 1050042216540652 |
oct | 114116465316775 |
9 | 20467784103577 |
10 | 5233230323197 |
11 | 17384450a6388 |
12 | 70629a2b6451 |
13 | 2bc650aa3176 |
14 | 14140ad11c29 |
15 | 911dd1ac667 |
hex | 4c274d59dfd |
5233230323197 has 2 divisors, whose sum is σ = 5233230323198. Its totient is φ = 5233230323196.
The previous prime is 5233230323159. The next prime is 5233230323201. The reversal of 5233230323197 is 7913230323325.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4836155163876 + 397075159321 = 2199126^2 + 630139^2 .
It is a cyclic number.
It is not a de Polignac number, because 5233230323197 - 211 = 5233230321149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5233230323137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2616615161598 + 2616615161599.
It is an arithmetic number, because the mean of its divisors is an integer number (2616615161599).
Almost surely, 25233230323197 is an apocalyptic number.
It is an amenable number.
5233230323197 is a deficient number, since it is larger than the sum of its proper divisors (1).
5233230323197 is an equidigital number, since it uses as much as digits as its factorization.
5233230323197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 612360, while the sum is 43.
The spelling of 5233230323197 in words is "five trillion, two hundred thirty-three billion, two hundred thirty million, three hundred twenty-three thousand, one hundred ninety-seven".
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