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52333150341 = 3411073976381
BaseRepresentation
bin110000101111010011…
…001000000010000101
312000002012001111012110
4300233103020002011
51324134241302331
640012545011233
73531602303223
oct605723100205
9160065044173
1052333150341
112021577647a
12a186323b19
134c20250a64
14276654bb13
151564613946
hexc2f4c8085

52333150341 has 16 divisors (see below), whose sum is σ = 72147475008. Its totient is φ = 33719702400.

The previous prime is 52333150321. The next prime is 52333150351. The reversal of 52333150341 is 14305133325.

It is not a de Polignac number, because 52333150341 - 211 = 52333148293 is a prime.

It is a super-2 number, since 2×523331503412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 52333150299 and 52333150308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (52333150321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1975030 + ... + 2001351.

It is an arithmetic number, because the mean of its divisors is an integer number (4509217188).

Almost surely, 252333150341 is an apocalyptic number.

It is an amenable number.

52333150341 is a deficient number, since it is larger than the sum of its proper divisors (19814324667).

52333150341 is a wasteful number, since it uses less digits than its factorization.

52333150341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3976532.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 52333150341 its reverse (14305133325), we get a palindrome (66638283666).

The spelling of 52333150341 in words is "fifty-two billion, three hundred thirty-three million, one hundred fifty thousand, three hundred forty-one".

Divisors: 1 3 41 107 123 321 4387 13161 3976381 11929143 163031621 425472767 489094863 1276418301 17444383447 52333150341