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52341132545021 is a prime number
BaseRepresentation
bin10111110011010100111101…
…00111001100101111111101
320212022202121112001221001102
423321222132213030233331
523330024114412420041
6303153103452422445
714011344025624055
oct1371523647145775
9225282545057042
1052341132545021
111574a827878031
125a5408b477a25
1323289946a2688
14ccd477d78565
1560b7a644709b
hex2f9a9e9ccbfd

52341132545021 has 2 divisors, whose sum is σ = 52341132545022. Its totient is φ = 52341132545020.

The previous prime is 52341132544957. The next prime is 52341132545029. The reversal of 52341132545021 is 12054523114325.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50969390311225 + 1371742233796 = 7139285^2 + 1171214^2 .

It is a cyclic number.

It is not a de Polignac number, because 52341132545021 - 26 = 52341132544957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52341132545029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26170566272510 + 26170566272511.

It is an arithmetic number, because the mean of its divisors is an integer number (26170566272511).

Almost surely, 252341132545021 is an apocalyptic number.

It is an amenable number.

52341132545021 is a deficient number, since it is larger than the sum of its proper divisors (1).

52341132545021 is an equidigital number, since it uses as much as digits as its factorization.

52341132545021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 52341132545021 its reverse (12054523114325), we get a palindrome (64395655659346).

The spelling of 52341132545021 in words is "fifty-two trillion, three hundred forty-one billion, one hundred thirty-two million, five hundred forty-five thousand, twenty-one".