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5234353314503 = 40336312976781
BaseRepresentation
bin100110000101011011111…
…0001010001101011000111
3200112101210002020000010012
41030022313301101223013
51141224423422031003
615044343445220435
71050112104032045
oct114126761215307
920471702200105
105234353314503
111738970a94375
1270655240171b
132bc79c643971
141414b6117395
1591256a858d8
hex4c2b7c51ac7

5234353314503 has 4 divisors (see below), whose sum is σ = 5234366694648. Its totient is φ = 5234339934360.

The previous prime is 5234353314481. The next prime is 5234353314511. The reversal of 5234353314503 is 3054133534325.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5234353314503 - 238 = 4959475407559 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5234353314583) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6085028 + ... + 6891753.

It is an arithmetic number, because the mean of its divisors is an integer number (1308591673662).

Almost surely, 25234353314503 is an apocalyptic number.

5234353314503 is a deficient number, since it is larger than the sum of its proper divisors (13380145).

5234353314503 is a wasteful number, since it uses less digits than its factorization.

5234353314503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13380144.

The product of its (nonzero) digits is 972000, while the sum is 41.

Adding to 5234353314503 its reverse (3054133534325), we get a palindrome (8288486848828).

The spelling of 5234353314503 in words is "five trillion, two hundred thirty-four billion, three hundred fifty-three million, three hundred fourteen thousand, five hundred three".

Divisors: 1 403363 12976781 5234353314503