Base | Representation |
---|---|
bin | 10111110011011100011011… |
… | …01010010010111010110111 |
3 | 20212100010222000122210210010 |
4 | 23321232031222102322313 |
5 | 23330110323114030401 |
6 | 303155005441031303 |
7 | 14011545305106216 |
oct | 1371561552227267 |
9 | 225303860583703 |
10 | 52345143111351 |
11 | 157514a5718962 |
12 | 5a54a0a625533 |
13 | 232918355364c |
14 | ccd73887d07d |
15 | 60b93d5a7ed6 |
hex | 2f9b8da92eb7 |
52345143111351 has 8 divisors (see below), whose sum is σ = 69847170213744. Its totient is φ = 34869939041600.
The previous prime is 52345143111343. The next prime is 52345143111353. The reversal of 52345143111351 is 15311134154325.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 52345143111351 - 23 = 52345143111343 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52345143111353) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6705753606 + ... + 6705761411.
It is an arithmetic number, because the mean of its divisors is an integer number (8730896276718).
Almost surely, 252345143111351 is an apocalyptic number.
52345143111351 is a deficient number, since it is larger than the sum of its proper divisors (17502027102393).
52345143111351 is a wasteful number, since it uses less digits than its factorization.
52345143111351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13411516321.
The product of its digits is 108000, while the sum is 39.
Adding to 52345143111351 its reverse (15311134154325), we get a palindrome (67656277265676).
The spelling of 52345143111351 in words is "fifty-two trillion, three hundred forty-five billion, one hundred forty-three million, one hundred eleven thousand, three hundred fifty-one".
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