Base | Representation |
---|---|
bin | 110000110011100010… |
… | …101101110111011101 |
3 | 12000021011000121202001 |
4 | 300303202231313131 |
5 | 1324311003040313 |
6 | 40024011002301 |
7 | 3533425410553 |
oct | 606342556735 |
9 | 160234017661 |
10 | 52404346333 |
11 | 20251984039 |
12 | a1a6139391 |
13 | 4c31c1aa71 |
14 | 2771ba1bd3 |
15 | 156a9c8add |
hex | c338adddd |
52404346333 has 2 divisors, whose sum is σ = 52404346334. Its totient is φ = 52404346332.
The previous prime is 52404346307. The next prime is 52404346339. The reversal of 52404346333 is 33364340425.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46609787449 + 5794558884 = 215893^2 + 76122^2 .
It is a cyclic number.
It is not a de Polignac number, because 52404346333 - 29 = 52404345821 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 52404346292 and 52404346301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52404346339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26202173166 + 26202173167.
It is an arithmetic number, because the mean of its divisors is an integer number (26202173167).
Almost surely, 252404346333 is an apocalyptic number.
It is an amenable number.
52404346333 is a deficient number, since it is larger than the sum of its proper divisors (1).
52404346333 is an equidigital number, since it uses as much as digits as its factorization.
52404346333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 311040, while the sum is 37.
Adding to 52404346333 its reverse (33364340425), we get a palindrome (85768686758).
The spelling of 52404346333 in words is "fifty-two billion, four hundred four million, three hundred forty-six thousand, three hundred thirty-three".
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