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5241113 is a prime number
BaseRepresentation
bin10011111111100100011001
3100212021110022
4103333210121
52320203423
6304200225
762356133
oct23774431
910767408
105241113
112a5a7a9
121909075
131116767
149a6053
156d7dc8
hex4ff919

5241113 has 2 divisors, whose sum is σ = 5241114. Its totient is φ = 5241112.

The previous prime is 5241107. The next prime is 5241143. The reversal of 5241113 is 3111425.

5241113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4443664 + 797449 = 2108^2 + 893^2 .

It is a cyclic number.

It is not a de Polignac number, because 5241113 - 28 = 5240857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5241091 and 5241100.

It is not a weakly prime, because it can be changed into another prime (5241143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2620556 + 2620557.

It is an arithmetic number, because the mean of its divisors is an integer number (2620557).

Almost surely, 25241113 is an apocalyptic number.

It is an amenable number.

5241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5241113 is an equidigital number, since it uses as much as digits as its factorization.

5241113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120, while the sum is 17.

The square root of 5241113 is about 2289.3477236977. The cubic root of 5241113 is about 173.7032087655.

Adding to 5241113 its reverse (3111425), we get a palindrome (8352538).

The spelling of 5241113 in words is "five million, two hundred forty-one thousand, one hundred thirteen".