Base | Representation |
---|---|
bin | 110000110101010010… |
… | …001000111011001111 |
3 | 12000100011222120201010 |
4 | 300311102020323033 |
5 | 1324340442231101 |
6 | 40030533020303 |
7 | 3534231602505 |
oct | 606522107317 |
9 | 160304876633 |
10 | 52433555151 |
11 | 2026741405a |
12 | a1b3a84693 |
13 | 4c37ca68a3 |
14 | 2775a06675 |
15 | 156d3482d6 |
hex | c35488ecf |
52433555151 has 4 divisors (see below), whose sum is σ = 69911406872. Its totient is φ = 34955703432.
The previous prime is 52433555117. The next prime is 52433555261. The reversal of 52433555151 is 15155533425.
52433555151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 52433555151 - 29 = 52433554639 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52433557151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8738925856 + ... + 8738925861.
It is an arithmetic number, because the mean of its divisors is an integer number (17477851718).
Almost surely, 252433555151 is an apocalyptic number.
52433555151 is a deficient number, since it is larger than the sum of its proper divisors (17477851721).
52433555151 is a wasteful number, since it uses less digits than its factorization.
52433555151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17477851720.
The product of its digits is 225000, while the sum is 39.
The spelling of 52433555151 in words is "fifty-two billion, four hundred thirty-three million, five hundred fifty-five thousand, one hundred fifty-one".
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