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52473000589 is a prime number
BaseRepresentation
bin110000110111101000…
…100111001010001101
312000102221012121200021
4300313220213022031
51324431042004324
640034502302141
73535221101002
oct606750471215
9160387177607
1052473000589
1120287705a99
12a205127951
134c43207b99
14277ad538a9
151571a3aae4
hexc37a2728d

52473000589 has 2 divisors, whose sum is σ = 52473000590. Its totient is φ = 52473000588.

The previous prime is 52473000583. The next prime is 52473000691. The reversal of 52473000589 is 98500037425.

52473000589 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 52255674025 + 217326564 = 228595^2 + 14742^2 .

It is a cyclic number.

It is not a de Polignac number, because 52473000589 - 25 = 52473000557 is a prime.

It is a super-4 number, since 4×524730005894 (a number of 44 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52473000583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26236500294 + 26236500295.

It is an arithmetic number, because the mean of its divisors is an integer number (26236500295).

Almost surely, 252473000589 is an apocalyptic number.

It is an amenable number.

52473000589 is a deficient number, since it is larger than the sum of its proper divisors (1).

52473000589 is an equidigital number, since it uses as much as digits as its factorization.

52473000589 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 43.

The spelling of 52473000589 in words is "fifty-two billion, four hundred seventy-three million, five hundred eighty-nine", and thus it is an aban number.