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5251111493 is a prime number
BaseRepresentation
bin1001110001111110…
…11001101001000101
3111112221220002202212
410320333121221011
541223241031433
62225021313205
7244061465645
oct47077315105
914487802685
105251111493
11225512a871
121026705805
13658ba0184
1437b58a525
1520b009d48
hex138fd9a45

5251111493 has 2 divisors, whose sum is σ = 5251111494. Its totient is φ = 5251111492.

The previous prime is 5251111477. The next prime is 5251111543. The reversal of 5251111493 is 3941111525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5101244929 + 149866564 = 71423^2 + 12242^2 .

It is a cyclic number.

It is not a de Polignac number, because 5251111493 - 24 = 5251111477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5251111433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625555746 + 2625555747.

It is an arithmetic number, because the mean of its divisors is an integer number (2625555747).

Almost surely, 25251111493 is an apocalyptic number.

It is an amenable number.

5251111493 is a deficient number, since it is larger than the sum of its proper divisors (1).

5251111493 is an equidigital number, since it uses as much as digits as its factorization.

5251111493 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5400, while the sum is 32.

The square root of 5251111493 is about 72464.5533554165. The cubic root of 5251111493 is about 1738.1359670991.

Adding to 5251111493 its sum of digits (32), we get a palindrome (5251111525).

The spelling of 5251111493 in words is "five billion, two hundred fifty-one million, one hundred eleven thousand, four hundred ninety-three".