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5251224205181 is a prime number
BaseRepresentation
bin100110001101010010101…
…0110100111011101111101
3200121000022211210001100002
41030122211112213131331
51142014001344031211
615100213515044045
71051250142162203
oct114324526473575
920530284701302
105251224205181
11174503918a229
12709880440625
132c125a970b06
141422369c9073
15918e2c5803b
hex4c6a55a777d

5251224205181 has 2 divisors, whose sum is σ = 5251224205182. Its totient is φ = 5251224205180.

The previous prime is 5251224205103. The next prime is 5251224205187. The reversal of 5251224205181 is 1815024221525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4763454661156 + 487769544025 = 2182534^2 + 698405^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5251224205181 is a prime.

It is a super-3 number, since 3×52512242051813 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5251224205187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625612102590 + 2625612102591.

It is an arithmetic number, because the mean of its divisors is an integer number (2625612102591).

Almost surely, 25251224205181 is an apocalyptic number.

It is an amenable number.

5251224205181 is a deficient number, since it is larger than the sum of its proper divisors (1).

5251224205181 is an equidigital number, since it uses as much as digits as its factorization.

5251224205181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64000, while the sum is 38.

The spelling of 5251224205181 in words is "five trillion, two hundred fifty-one billion, two hundred twenty-four million, two hundred five thousand, one hundred eighty-one".