52513101131 has 4 divisors (see below), whose sum is σ = 52514715912. Its totient is φ = 52511486352.

The previous prime is 52513101127. The next prime is 52513101191. The reversal of 52513101131 is 13110131525.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52513101131 - 2² = 52513101127 is a prime.

It is a super-2 number, since 2×52513101131² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 52513101097 and 52513101106.

It is not an unprimeable number, because it can be changed into a prime (52513101191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 757586 + ... + 823991.

It is an arithmetic number, because the mean of its divisors is an integer number (13128678978).

Almost surely, 2^52513101131 is an apocalyptic number.

52513101131 is a deficient number, since it is larger than the sum of its proper divisors (1614781).

52513101131 is a wasteful number, since it uses less digits than its factorization.

52513101131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1614780.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 52513101131 its reverse (13110131525), we get a palindrome (65623232656).

The spelling of 52513101131 in words is "fifty-two billion, five hundred thirteen million, one hundred one thousand, one hundred thirty-one".