Base | Representation |
---|---|
bin | 100110001101010101001… |
… | …1111001101000100010111 |
3 | 200121000112211212021102022 |
4 | 1030122222133031010113 |
5 | 1142014140421424143 |
6 | 15100230233203355 |
7 | 1051252236266165 |
oct | 114325237150427 |
9 | 20530484767368 |
10 | 5251310342423 |
11 | 1745082872432 |
12 | 7098a526055b |
13 | 2c127276c7b2 |
14 | 14224420c235 |
15 | 918ea5c0268 |
hex | 4c6aa7cd117 |
5251310342423 has 2 divisors, whose sum is σ = 5251310342424. Its totient is φ = 5251310342422.
The previous prime is 5251310342413. The next prime is 5251310342431. The reversal of 5251310342423 is 3242430131525.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5251310342423 - 230 = 5250236600599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5251310342413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2625655171211 + 2625655171212.
It is an arithmetic number, because the mean of its divisors is an integer number (2625655171212).
Almost surely, 25251310342423 is an apocalyptic number.
5251310342423 is a deficient number, since it is larger than the sum of its proper divisors (1).
5251310342423 is an equidigital number, since it uses as much as digits as its factorization.
5251310342423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 5251310342423 its reverse (3242430131525), we get a palindrome (8493740473948).
The spelling of 5251310342423 in words is "five trillion, two hundred fifty-one billion, three hundred ten million, three hundred forty-two thousand, four hundred twenty-three".
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