52513401399959 has 2 divisors, whose sum is σ = 52513401399960. Its totient is φ = 52513401399958.

The previous prime is 52513401399941. The next prime is 52513401400063. The reversal of 52513401399959 is 95999310431525.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-52513401399959 is a prime.

It is a super-2 number, since 2×52513401399959² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 52513401399895 and 52513401399904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52513401399059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26256700699979 + 26256700699980.

It is an arithmetic number, because the mean of its divisors is an integer number (26256700699980).

Almost surely, 2^{52513401399959} is an apocalyptic number.

52513401399959 is a deficient number, since it is larger than the sum of its proper divisors (1).

52513401399959 is an equidigital number, since it uses as much as digits as its factorization.

52513401399959 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 59049000, while the sum is 65.

The spelling of 52513401399959 in words is "fifty-two trillion, five hundred thirteen billion, four hundred one million, three hundred ninety-nine thousand, nine hundred fifty-nine".