Base | Representation |
---|---|
bin | 10111111000010101110101… |
… | …01000101110101011000010 |
3 | 20212221020021020022111002200 |
4 | 23330022322220232223002 |
5 | 23340334421224300002 |
6 | 303404153520054030 |
7 | 14026653020005554 |
oct | 1374127250565302 |
9 | 225836236274080 |
10 | 52513401400002 |
11 | 15806899083564 |
12 | 5a81547a64316 |
13 | 233bcb96b86aa |
14 | cd793b0934d4 |
15 | 610eda060b1c |
hex | 2fc2baa2eac2 |
52513401400002 has 96 divisors (see below), whose sum is σ = 117509653857024. Its totient is φ = 16939866528000.
The previous prime is 52513401399959. The next prime is 52513401400063. The reversal of 52513401400002 is 20000410431525.
52513401400002 is a `hidden beast` number, since 5 + 2 + 513 + 4 + 0 + 140 + 0 + 0 + 0 + 2 = 666.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 29843502 + ... + 31554102.
It is an arithmetic number, because the mean of its divisors is an integer number (1224058894344).
Almost surely, 252513401400002 is an apocalyptic number.
52513401400002 is an abundant number, since it is smaller than the sum of its proper divisors (64996252457022).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
52513401400002 is a wasteful number, since it uses less digits than its factorization.
52513401400002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1711064 (or 1711061 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 27.
Adding to 52513401400002 its reverse (20000410431525), we get a palindrome (72513811831527).
The spelling of 52513401400002 in words is "fifty-two trillion, five hundred thirteen billion, four hundred one million, four hundred thousand, two".
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