52513401400003 has 4 divisors (see below), whose sum is σ = 53932682518960. Its totient is φ = 51094120281048.

The previous prime is 52513401399959. The next prime is 52513401400063. The reversal of 52513401400003 is 30000410431525.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 52513401400003 - 2⁹ = 52513401399491 is a prime.

It is not an unprimeable number, because it can be changed into a prime (52513401400063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 709640559423 + ... + 709640559496.

It is an arithmetic number, because the mean of its divisors is an integer number (13483170629740).

Almost surely, 2^{52513401400003} is an apocalyptic number.

52513401400003 is a deficient number, since it is larger than the sum of its proper divisors (1419281118957).

52513401400003 is a wasteful number, since it uses less digits than its factorization.

52513401400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1419281118956.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 52513401400003 its reverse (30000410431525), we get a palindrome (82513811831528).

The spelling of 52513401400003 in words is "fifty-two trillion, five hundred thirteen billion, four hundred one million, four hundred thousand, three".