Base | Representation |
---|---|
bin | 110000111010000110… |
… | …111111001011000111 |
3 | 12000112211022220110011 |
4 | 300322012333023013 |
5 | 1330022204031303 |
6 | 40042544211051 |
7 | 3536234015104 |
oct | 607206771307 |
9 | 160484286404 |
10 | 52514517703 |
11 | 202a909245a |
12 | a217009a87 |
13 | 4c4b9b311b |
14 | 278267daab |
15 | 15754dc16d |
hex | c3a1bf2c7 |
52514517703 has 4 divisors (see below), whose sum is σ = 52515010648. Its totient is φ = 52514024760.
The previous prime is 52514517691. The next prime is 52514517707. The reversal of 52514517703 is 30771541525.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 52514517703 - 213 = 52514509511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52514517707) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12876 + ... + 324337.
It is an arithmetic number, because the mean of its divisors is an integer number (13128752662).
Almost surely, 252514517703 is an apocalyptic number.
52514517703 is a deficient number, since it is larger than the sum of its proper divisors (492945).
52514517703 is a wasteful number, since it uses less digits than its factorization.
52514517703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 492944.
The product of its (nonzero) digits is 147000, while the sum is 40.
The spelling of 52514517703 in words is "fifty-two billion, five hundred fourteen million, five hundred seventeen thousand, seven hundred three".
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