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5252600166117 = 31750866722039
BaseRepresentation
bin100110001101111011101…
…0111011111011011100101
3200121010212201220002220020
41030123313113133123211
51142024311120303432
615101002230425353
71051326220514133
oct114336727373345
920533781802806
105252600166117
11174568494a027
12709ba5202259
132c1419a53895
14142327640753
159197395022c
hex4c6f75df6e5

5252600166117 has 4 divisors (see below), whose sum is σ = 7003466888160. Its totient is φ = 3501733444076.

The previous prime is 5252600166097. The next prime is 5252600166131. The reversal of 5252600166117 is 7116610062525.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5252600166117 - 28 = 5252600165861 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5252600166157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 875433361017 + ... + 875433361022.

It is an arithmetic number, because the mean of its divisors is an integer number (1750866722040).

Almost surely, 25252600166117 is an apocalyptic number.

It is an amenable number.

5252600166117 is a deficient number, since it is larger than the sum of its proper divisors (1750866722043).

5252600166117 is a wasteful number, since it uses less digits than its factorization.

5252600166117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1750866722042.

The product of its (nonzero) digits is 151200, while the sum is 42.

The spelling of 5252600166117 in words is "five trillion, two hundred fifty-two billion, six hundred million, one hundred sixty-six thousand, one hundred seventeen".

Divisors: 1 3 1750866722039 5252600166117