Base | Representation |
---|---|
bin | 10111111000110110111000… |
… | …00000001000111101001011 |
3 | 20212222221001112121021221022 |
4 | 23330123130000020331023 |
5 | 23341132234102214113 |
6 | 303420250102303055 |
7 | 14031151434406343 |
oct | 1374333400107513 |
9 | 225887045537838 |
10 | 52531141054283 |
11 | 15813371706371 |
12 | 5a84a78a27a8b |
13 | 23408859c3548 |
14 | cd87410add23 |
15 | 6116c763e908 |
hex | 2fc6dc008f4b |
52531141054283 has 2 divisors, whose sum is σ = 52531141054284. Its totient is φ = 52531141054282.
The previous prime is 52531141054277. The next prime is 52531141054391. The reversal of 52531141054283 is 38245014113525.
52531141054283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 52531141054283 - 214 = 52531141037899 is a prime.
It is not a weakly prime, because it can be changed into another prime (52531141054243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26265570527141 + 26265570527142.
It is an arithmetic number, because the mean of its divisors is an integer number (26265570527142).
Almost surely, 252531141054283 is an apocalyptic number.
52531141054283 is a deficient number, since it is larger than the sum of its proper divisors (1).
52531141054283 is an equidigital number, since it uses as much as digits as its factorization.
52531141054283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576000, while the sum is 44.
The spelling of 52531141054283 in words is "fifty-two trillion, five hundred thirty-one billion, one hundred forty-one million, fifty-four thousand, two hundred eighty-three".
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