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525314465141 is a prime number
BaseRepresentation
bin1111010010011110010…
…11101001110101110101
31212012221001211210010112
413221033023221311311
532101321000341031
61041154240032405
752644532164614
oct7511713516565
91765831753115
10525314465141
1119286a358874
1285986902705
133a6c987812b
141b5d526787b
15d9e822062b
hex7a4f2e9d75

525314465141 has 2 divisors, whose sum is σ = 525314465142. Its totient is φ = 525314465140.

The previous prime is 525314465131. The next prime is 525314465243. The reversal of 525314465141 is 141564413525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 395477476900 + 129836988241 = 628870^2 + 360329^2 .

It is a cyclic number.

It is not a de Polignac number, because 525314465141 - 218 = 525314202997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (525314465131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 262657232570 + 262657232571.

It is an arithmetic number, because the mean of its divisors is an integer number (262657232571).

Almost surely, 2525314465141 is an apocalyptic number.

It is an amenable number.

525314465141 is a deficient number, since it is larger than the sum of its proper divisors (1).

525314465141 is an equidigital number, since it uses as much as digits as its factorization.

525314465141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 288000, while the sum is 41.

Adding to 525314465141 its reverse (141564413525), we get a palindrome (666878878666).

The spelling of 525314465141 in words is "five hundred twenty-five billion, three hundred fourteen million, four hundred sixty-five thousand, one hundred forty-one".