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5253330050335 = 544310512256619
BaseRepresentation
bin100110001110010001011…
…0111110001110100011111
3200121012202121022001211001
41030130202313301310133
51142032304443102320
615101202502411131
71051353262442353
oct114344267616437
920535677261731
105253330050335
111745a1994a924
1270a169730aa7
132c1505027333
14142396557463
15919b7a7720a
hex4c722df1d1f

5253330050335 has 16 divisors (see below), whose sum is σ = 6324240735360. Its totient is φ = 4189185655200.

The previous prime is 5253330050323. The next prime is 5253330050357. The reversal of 5253330050335 is 5330500333525.

5253330050335 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a de Polignac number, because none of the positive numbers 2k-5253330050335 is a prime.

It is a super-2 number, since 2×52533300503352 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5253330050294 and 5253330050303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1199656 + ... + 3456274.

It is an arithmetic number, because the mean of its divisors is an integer number (395265045960).

Almost surely, 25253330050335 is an apocalyptic number.

5253330050335 is a deficient number, since it is larger than the sum of its proper divisors (1070910685025).

5253330050335 is a wasteful number, since it uses less digits than its factorization.

5253330050335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2258118.

The product of its (nonzero) digits is 303750, while the sum is 37.

The spelling of 5253330050335 in words is "five trillion, two hundred fifty-three billion, three hundred thirty million, fifty thousand, three hundred thirty-five".

Divisors: 1 5 443 1051 2215 5255 465593 2256619 2327965 11283095 999682217 2371706569 4998411085 11858532845 1050666010067 5253330050335