Base | Representation |
---|---|
bin | 111011101110011000111111… |
… | …0100000000011110101001010 |
3 | 2112220002112011011021012102212 |
4 | 1313130301332200003311022 |
5 | 1022324224230040023200 |
6 | 5101152152440225122 |
7 | 215440643213322026 |
oct | 16734617640036512 |
9 | 2486075134235385 |
10 | 525345342111050 |
11 | 14243378799580a |
12 | 4ab0754416b1a2 |
13 | 19719b12601b96 |
14 | 93a2bc9047386 |
15 | 40b068812e035 |
hex | 1ddcc7e803d4a |
525345342111050 has 24 divisors (see below), whose sum is σ = 1028570880345600. Its totient is φ = 199078234904880.
The previous prime is 525345342111047. The next prime is 525345342111071. The reversal of 525345342111050 is 50111243543525.
It is a junction number, because it is equal to n+sod(n) for n = 525345342110989 and 525345342111007.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 276497547530 + ... + 276497549429.
It is an arithmetic number, because the mean of its divisors is an integer number (42857120014400).
Almost surely, 2525345342111050 is an apocalyptic number.
525345342111050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
525345342111050 is a deficient number, since it is larger than the sum of its proper divisors (503225538234550).
525345342111050 is a wasteful number, since it uses less digits than its factorization.
525345342111050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 552995096990 (or 552995096985 counting only the distinct ones).
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 525345342111050 its reverse (50111243543525), we get a palindrome (575456585654575).
The spelling of 525345342111050 in words is "five hundred twenty-five trillion, three hundred forty-five billion, three hundred forty-two million, one hundred eleven thousand, fifty".
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