Base | Representation |
---|---|
bin | 10111111000111110010110… |
… | …00110111111001101111111 |
3 | 20220000022102010001010122220 |
4 | 23330133023012333031333 |
5 | 23341213443031312111 |
6 | 303422152123540423 |
7 | 14031353025125556 |
oct | 1374371306771577 |
9 | 226008363033586 |
10 | 52535152604031 |
11 | 15815040069039 |
12 | 5a857b838a713 |
13 | 2341074b2a016 |
14 | cd8a01b8cd9d |
15 | 61185e8e6e06 |
hex | 2fc7cb1bf37f |
52535152604031 has 8 divisors (see below), whose sum is σ = 70208641203120. Its totient is φ = 34942549537152.
The previous prime is 52535152604003. The next prime is 52535152604041. The reversal of 52535152604031 is 13040625153525.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 52535152604031 - 242 = 48137106092927 is a prime.
It is a super-2 number, since 2×525351526040312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52535152604041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20221381536 + ... + 20221384133.
It is an arithmetic number, because the mean of its divisors is an integer number (8776080150390).
Almost surely, 252535152604031 is an apocalyptic number.
52535152604031 is a deficient number, since it is larger than the sum of its proper divisors (17673488599089).
52535152604031 is a wasteful number, since it uses less digits than its factorization.
52535152604031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40442766105.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 52535152604031 its reverse (13040625153525), we get a palindrome (65575777757556).
The spelling of 52535152604031 in words is "fifty-two trillion, five hundred thirty-five billion, one hundred fifty-two million, six hundred four thousand, thirty-one".
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