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52535310535277 is a prime number
BaseRepresentation
bin10111111000111110101001…
…00001011100101001101101
320220000022211010012212121022
423330133110201130221231
523341214303444112102
6303422215524543525
714031356653410533
oct1374372441345155
9226008733185538
1052535310535277
1115815111228129
125a85841251ba5
13234109b774c6b
14cd8a18b40153
1561186d6e15a2
hex2fc7d485ca6d

52535310535277 has 2 divisors, whose sum is σ = 52535310535278. Its totient is φ = 52535310535276.

The previous prime is 52535310535217. The next prime is 52535310535319. The reversal of 52535310535277 is 77253501353525.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47757650097481 + 4777660437796 = 6910691^2 + 2185786^2 .

It is a cyclic number.

It is not a de Polignac number, because 52535310535277 - 214 = 52535310518893 is a prime.

It is a super-2 number, since 2×525353105352772 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (52535310535217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26267655267638 + 26267655267639.

It is an arithmetic number, because the mean of its divisors is an integer number (26267655267639).

Almost surely, 252535310535277 is an apocalyptic number.

It is an amenable number.

52535310535277 is a deficient number, since it is larger than the sum of its proper divisors (1).

52535310535277 is an equidigital number, since it uses as much as digits as its factorization.

52535310535277 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16537500, while the sum is 53.

The spelling of 52535310535277 in words is "fifty-two trillion, five hundred thirty-five billion, three hundred ten million, five hundred thirty-five thousand, two hundred seventy-seven".