Base | Representation |
---|---|
bin | 111011101110101001011000… |
… | …1010111011000110011111011 |
3 | 2112220012220001012221011202210 |
4 | 1313131102301113120303323 |
5 | 1022330313334113322300 |
6 | 5101220254535230203 |
7 | 215443330633625001 |
oct | 16735226127306373 |
9 | 2486186035834683 |
10 | 525380555214075 |
11 | 142447707859250 |
12 | 4ab12330b18363 |
13 | 19720234a19c12 |
14 | 93a47a9986a71 |
15 | 40b1549756050 |
hex | 1ddd4b15d8cfb |
525380555214075 has 48 divisors (see below), whose sum is σ = 947892810370176. Its totient is φ = 254650037068800.
The previous prime is 525380555214041. The next prime is 525380555214103. The reversal of 525380555214075 is 570412555083525.
It is not a de Polignac number, because 525380555214075 - 234 = 525363375344891 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 97280502 + ... + 102539051.
It is an arithmetic number, because the mean of its divisors is an integer number (19747766882712).
Almost surely, 2525380555214075 is an apocalyptic number.
525380555214075 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
525380555214075 is a deficient number, since it is larger than the sum of its proper divisors (422512255156101).
525380555214075 is a wasteful number, since it uses less digits than its factorization.
525380555214075 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 199822764 (or 199822759 counting only the distinct ones).
The product of its (nonzero) digits is 42000000, while the sum is 57.
The spelling of 525380555214075 in words is "five hundred twenty-five trillion, three hundred eighty billion, five hundred fifty-five million, two hundred fourteen thousand, seventy-five".
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