Base | Representation |
---|---|
bin | 110000111011101010… |
… | …100111010000011101 |
3 | 12000121122110202110122 |
4 | 300323222213100131 |
5 | 1330100400243031 |
6 | 40045320044325 |
7 | 3540002010242 |
oct | 607352472035 |
9 | 160548422418 |
10 | 52540634141 |
11 | 20311900096 |
12 | a2239036a5 |
13 | 4c54228538 |
14 | 2785d1b5c9 |
15 | 157794a47b |
hex | c3baa741d |
52540634141 has 2 divisors, whose sum is σ = 52540634142. Its totient is φ = 52540634140.
The previous prime is 52540634093. The next prime is 52540634147. The reversal of 52540634141 is 14143604525.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40825818916 + 11714815225 = 202054^2 + 108235^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52540634141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (52540634147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26270317070 + 26270317071.
It is an arithmetic number, because the mean of its divisors is an integer number (26270317071).
Almost surely, 252540634141 is an apocalyptic number.
It is an amenable number.
52540634141 is a deficient number, since it is larger than the sum of its proper divisors (1).
52540634141 is an equidigital number, since it uses as much as digits as its factorization.
52540634141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 35.
The spelling of 52540634141 in words is "fifty-two billion, five hundred forty million, six hundred thirty-four thousand, one hundred forty-one".
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