Base | Representation |
---|---|
bin | 110000111011110100… |
… | …110100110111001111 |
3 | 12000121211111202212002 |
4 | 300323310310313033 |
5 | 1330102041430221 |
6 | 40045453302515 |
7 | 3540033530351 |
oct | 607364646717 |
9 | 160554452762 |
10 | 52543311311 |
11 | 20313369527 |
12 | a224794a3b |
13 | 4c54954c6a |
14 | 27864170d1 |
15 | 1577cc880b |
hex | c3bd34dcf |
52543311311 has 8 divisors (see below), whose sum is σ = 52724721840. Its totient is φ = 52362191808.
The previous prime is 52543311287. The next prime is 52543311319. The reversal of 52543311311 is 11311334525.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-52543311311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (52543311319) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 292100 + ... + 436358.
It is an arithmetic number, because the mean of its divisors is an integer number (6590590230).
Almost surely, 252543311311 is an apocalyptic number.
52543311311 is a deficient number, since it is larger than the sum of its proper divisors (181410529).
52543311311 is a wasteful number, since it uses less digits than its factorization.
52543311311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145513.
The product of its digits is 5400, while the sum is 29.
Adding to 52543311311 its reverse (11311334525), we get a palindrome (63854645836).
The spelling of 52543311311 in words is "fifty-two billion, five hundred forty-three million, three hundred eleven thousand, three hundred eleven".
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