Base | Representation |
---|---|
bin | 110000111011110111… |
… | …111000010111110001 |
3 | 12000121220000110100102 |
4 | 300323313320113301 |
5 | 1330102243041423 |
6 | 40045522402145 |
7 | 3540043404143 |
oct | 607367702761 |
9 | 160556013312 |
10 | 52544112113 |
11 | 20313866149 |
12 | a224b00355 |
13 | 4c54b755cc |
14 | 2786584c93 |
15 | 1577dd5c28 |
hex | c3bdf85f1 |
52544112113 has 2 divisors, whose sum is σ = 52544112114. Its totient is φ = 52544112112.
The previous prime is 52544112037. The next prime is 52544112157. The reversal of 52544112113 is 31121144525.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38270314384 + 14273797729 = 195628^2 + 119473^2 .
It is a cyclic number.
It is not a de Polignac number, because 52544112113 - 212 = 52544108017 is a prime.
It is not a weakly prime, because it can be changed into another prime (52544112013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26272056056 + 26272056057.
It is an arithmetic number, because the mean of its divisors is an integer number (26272056057).
Almost surely, 252544112113 is an apocalyptic number.
It is an amenable number.
52544112113 is a deficient number, since it is larger than the sum of its proper divisors (1).
52544112113 is an equidigital number, since it uses as much as digits as its factorization.
52544112113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4800, while the sum is 29.
Adding to 52544112113 its reverse (31121144525), we get a palindrome (83665256638).
The spelling of 52544112113 in words is "fifty-two billion, five hundred forty-four million, one hundred twelve thousand, one hundred thirteen".
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