Base | Representation |
---|---|
bin | 100110001111010010001… |
… | …0111000001110001011011 |
3 | 200121102101000011002121222 |
4 | 1030132210113001301123 |
5 | 1142101232120044003 |
6 | 15102202225522255 |
7 | 1051461152126534 |
oct | 114364427016133 |
9 | 20542330132558 |
10 | 5255502503003 |
11 | 1746934174755 |
12 | 70a6751a338b |
13 | 2c179013219c |
14 | 142520ca368b |
15 | 91a93651c38 |
hex | 4c7a45c1c5b |
5255502503003 has 8 divisors (see below), whose sum is σ = 5569475965488. Its totient is φ = 4942065291264.
The previous prime is 5255502502951. The next prime is 5255502503051. The reversal of 5255502503003 is 3003052055525.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5255502503003 - 222 = 5255498308699 is a prime.
It is a super-3 number, since 3×52555025030033 (a number of 39 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (5255502503093) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 134042501 + ... + 134081702.
It is an arithmetic number, because the mean of its divisors is an integer number (696184495686).
Almost surely, 25255502503003 is an apocalyptic number.
5255502503003 is a deficient number, since it is larger than the sum of its proper divisors (313973462485).
5255502503003 is a wasteful number, since it uses less digits than its factorization.
5255502503003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 268125373.
The product of its (nonzero) digits is 112500, while the sum is 35.
Adding to 5255502503003 its reverse (3003052055525), we get a palindrome (8258554558528).
The spelling of 5255502503003 in words is "five trillion, two hundred fifty-five billion, five hundred two million, five hundred three thousand, three".
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