Base | Representation |
---|---|
bin | 1001110011000010… |
… | …00101010010010011 |
3 | 111120120111200121001 |
4 | 10321201011102103 |
5 | 41233021103021 |
6 | 2225534442431 |
7 | 244226521663 |
oct | 47141052223 |
9 | 14516450531 |
10 | 5259941011 |
11 | 225a110596 |
12 | 1029663417 |
13 | 65a972040 |
14 | 37c8081a3 |
15 | 20bba1091 |
hex | 139845493 |
5259941011 has 4 divisors (see below), whose sum is σ = 5664551872. Its totient is φ = 4855330152.
The previous prime is 5259941009. The next prime is 5259941017. The reversal of 5259941011 is 1101499525.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5259941011 - 21 = 5259941009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5259941017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202305411 + ... + 202305436.
It is an arithmetic number, because the mean of its divisors is an integer number (1416137968).
Almost surely, 25259941011 is an apocalyptic number.
5259941011 is a deficient number, since it is larger than the sum of its proper divisors (404610861).
5259941011 is a wasteful number, since it uses less digits than its factorization.
5259941011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 404610860.
The product of its (nonzero) digits is 16200, while the sum is 37.
The square root of 5259941011 is about 72525.4507810879. The cubic root of 5259941011 is about 1739.1096218600.
The spelling of 5259941011 in words is "five billion, two hundred fifty-nine million, nine hundred forty-one thousand, eleven".
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