Base | Representation |
---|---|
bin | 100110010010110001000… |
… | …0110011111010001000111 |
3 | 200122010200011220020101001 |
4 | 1030211202012133101013 |
5 | 1142212041041240303 |
6 | 15105440251514131 |
7 | 1052144366504365 |
oct | 114454206372107 |
9 | 20563604806331 |
10 | 5262980805703 |
11 | 174a021506205 |
12 | 710001758947 |
13 | 2c23b256437a |
14 | 142a30168635 |
15 | 91d7ee4a31d |
hex | 4c96219f447 |
5262980805703 has 2 divisors, whose sum is σ = 5262980805704. Its totient is φ = 5262980805702.
The previous prime is 5262980805629. The next prime is 5262980805713. The reversal of 5262980805703 is 3075080892625.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5262980805703 - 217 = 5262980674631 is a prime.
It is a super-2 number, since 2×52629808057032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5262980805713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2631490402851 + 2631490402852.
It is an arithmetic number, because the mean of its divisors is an integer number (2631490402852).
Almost surely, 25262980805703 is an apocalyptic number.
5262980805703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5262980805703 is an equidigital number, since it uses as much as digits as its factorization.
5262980805703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 55.
The spelling of 5262980805703 in words is "five trillion, two hundred sixty-two billion, nine hundred eighty million, eight hundred five thousand, seven hundred three".
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