Base | Representation |
---|---|
bin | 100110010011110001001… |
… | …0101110110001101110111 |
3 | 200122100020010100020222111 |
4 | 1030213202111312031313 |
5 | 1142230442333044021 |
6 | 15110433550111451 |
7 | 1052251613154625 |
oct | 114474225661567 |
9 | 20570203306874 |
10 | 5265132315511 |
11 | 174aa25a26392 |
12 | 7105021ab587 |
13 | 2c26662188b3 |
14 | 142b95bc2515 |
15 | 91e58c898e1 |
hex | 4c9e2576377 |
5265132315511 has 2 divisors, whose sum is σ = 5265132315512. Its totient is φ = 5265132315510.
The previous prime is 5265132315491. The next prime is 5265132315643. The reversal of 5265132315511 is 1155132315625.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5265132315511 - 223 = 5265123926903 is a prime.
It is a super-3 number, since 3×52651323155113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5265132315011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2632566157755 + 2632566157756.
It is an arithmetic number, because the mean of its divisors is an integer number (2632566157756).
Almost surely, 25265132315511 is an apocalyptic number.
5265132315511 is a deficient number, since it is larger than the sum of its proper divisors (1).
5265132315511 is an equidigital number, since it uses as much as digits as its factorization.
5265132315511 is an evil number, because the sum of its binary digits is even.
The product of its digits is 135000, while the sum is 40.
The spelling of 5265132315511 in words is "five trillion, two hundred sixty-five billion, one hundred thirty-two million, three hundred fifteen thousand, five hundred eleven".
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