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5268375009917 is a prime number
BaseRepresentation
bin100110010101010001110…
…0111101111101001111101
3200122122121010001012110022
41030222203213233221331
51142304113000304132
615112131424221525
71052425146464315
oct114524347575175
920578533035408
105268375009917
11175133a38a718
1271106816a8a5
132c2a61c85496
14142dc2722445
15920987bce12
hex4caa39efa7d

5268375009917 has 2 divisors, whose sum is σ = 5268375009918. Its totient is φ = 5268375009916.

The previous prime is 5268375009913. The next prime is 5268375010027. The reversal of 5268375009917 is 7199005738625.

5268375009917 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4742381645401 + 525993364516 = 2177701^2 + 725254^2 .

It is a cyclic number.

It is not a de Polignac number, because 5268375009917 - 22 = 5268375009913 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5268375009917.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5268375009913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2634187504958 + 2634187504959.

It is an arithmetic number, because the mean of its divisors is an integer number (2634187504959).

Almost surely, 25268375009917 is an apocalyptic number.

It is an amenable number.

5268375009917 is a deficient number, since it is larger than the sum of its proper divisors (1).

5268375009917 is an equidigital number, since it uses as much as digits as its factorization.

5268375009917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28576800, while the sum is 62.

The spelling of 5268375009917 in words is "five trillion, two hundred sixty-eight billion, three hundred seventy-five million, nine thousand, nine hundred seventeen".