Base | Representation |
---|---|
bin | 100110011001001010000… |
… | …1000001100001111000011 |
3 | 200200110002122102021211211 |
4 | 1030302110020030033003 |
5 | 1142423142440432343 |
6 | 15120030153150551 |
7 | 1053141445402522 |
oct | 114622410141703 |
9 | 20613078367754 |
10 | 5276705014723 |
11 | 175492446560a |
12 | 7127b19bb457 |
13 | 2c378b9a05cc |
14 | 143572b704b9 |
15 | 923d4c5279d |
hex | 4cc9420c3c3 |
5276705014723 has 2 divisors, whose sum is σ = 5276705014724. Its totient is φ = 5276705014722.
The previous prime is 5276705014709. The next prime is 5276705014753. The reversal of 5276705014723 is 3274105076725.
5276705014723 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5276705014723 is a prime.
It is an alternating number because its digits alternate between odd and even.
It is not a weakly prime, because it can be changed into another prime (5276705014753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2638352507361 + 2638352507362.
It is an arithmetic number, because the mean of its divisors is an integer number (2638352507362).
Almost surely, 25276705014723 is an apocalyptic number.
5276705014723 is a deficient number, since it is larger than the sum of its proper divisors (1).
5276705014723 is an equidigital number, since it uses as much as digits as its factorization.
5276705014723 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2469600, while the sum is 49.
The spelling of 5276705014723 in words is "five trillion, two hundred seventy-six billion, seven hundred five million, fourteen thousand, seven hundred twenty-three".
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